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Salamander Ceramic Infrared Emitters Technical Manual Page 19
Water Evaporation Example (continued):
R = (.84)(36.58072 x 10 -12 )( ( T1
)4 - ( T2 )4 ) = 16.27
Where: T1 = Source Temperature
T2 = Average Water Temperature = (65+212)/2 = 138.5 °F (59 °C)
= 332.5 K
Solve the equation for the source temperature.
= 858 K = 1084 °F (584 °C)
Results: The surface temperature of the source must be at least 1084 °F (584 °C) to evaporate 4 grams of water within 5 seconds.
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